Math, asked by prachisubarna, 1 year ago

find the derivative of this equation & pls explain it​

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Anonymous: Mark my ans as brainlist if u found it helpful
prachisubarna: it helpful
prachisubarna: but the ans given in my book is different
Anonymous: what is ans given in book.
Anonymous: what is the given in the book?
prachisubarna: - cosx/sin^2x+ cotx
Anonymous: yeah this one is also its ans after simplification
Anonymous: let me edit my ans.
prachisubarna: ok
Anonymous: wait

Answers

Answered by harshitas273
2

derivative of cosecx= -cosecx . cotx

derivative of cotx = - cosec^2(x)

so answer will be= -cosecx( cotx + cosecx)

Answered by Anonymous
4

Hie!!

d/dx ( Cosec x + Cot x )

= - Cosec x Cot x + (- Cosec² x )

= - Cosec x { Cot x + Cosec x }

= -1/Sin x { Cos x / Sin x + 1/Sin x }

= -1/Sin x { Cos x / Sin x }

= { - Cos x } / Sin² x

Note:-

Differentiation of Cosec x is - Cosec x × Cot x

And

Differentiation of Cot x is - Cosec² x

Cosec x = 1/ Sin x

And

Cot x = Cos x / Sin x


prachisubarna: thank you very much
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