Math, asked by mukhtar7867, 1 year ago

Find the derivative of x^2+e^x at x=0

Answers

Answered by gangwarakash999

Hey mate your ans is here.....

Give:

y=x^2 + e^x. ( AT X = 0 )

diff. with respect to x

dy/dx = 2x + e^x

dy/dx = 2 * 0 + e^0

dy/dx = 0 + 1

dy/dx = 1

so the derivative of y = x^2 + e^x , at x = 0, will be 1.

Hope it helps.

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