Question

. Find the derivative of x^2sin2x from first principle.​

Answer 1

Answer:

let y=x² sin 2x

dy/dx = x²d/dx sin2x + sin2x d/dx x²

dy/dx = x²cos2x d/dx 2x + sin2x × 2x

dy/dx = 2x²cos2x + 2x sin2x

dy/dx = 2x ( xcos2x + sin2x)

Answer 2

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