Question

find the derivative of x^3(5+3x)​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

dx

dxd

dxd

dxd (x

dxd (x −3

dxd (x −3 (5+3x))

dxd (x −3 (5+3x))=

dxd (x −3 (5+3x))= dx

dxd (x −3 (5+3x))= dxd

dxd (x −3 (5+3x))= dxd

dxd (x −3 (5+3x))= dxd (5x

dxd (x −3 (5+3x))= dxd (5x −3

dxd (x −3 (5+3x))= dxd (5x −3 +3x

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )=

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )= dx

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )= dxd

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )= dxd

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )= dxd (5x

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )= dxd (5x −3

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )= dxd (5x −3 +3x

dxd (x −3 (5+3x))= dxd (5x −3 +3x 1−3 )= dxd (5x −3 +3x −2

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