Math, asked by Anonymous, 1 year ago

find the derivative of x.cosx by using the formulas of the derivatives.

Answers

Answered by Jahnvi97
4
Use the formula, d/dx(u*v) = u* d/dx(v) + v* d/dx(u)

d/dx(x*cosx)
= x* d/dx(cosx) + cosx* d/dx(x)
= x*(-sinx) + cosx * 1
= -x.sinx + cosx

Jahnvi97: Thanks Raksha!
Anonymous: Deeksha!!
Answered by Anonymous
3
Okay.... !! Let , y = xcosx ------(1) Using product rule , d/dx[f(x).g(x)] = f(x).d/dx{g(x)} + g(x).d/dx{f(x)} Differentiating equation 1 w.r.t. 'x' dy/dx = x(-sinx) + cosx dy/dx = cosx - xsinx
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