Question

find the derivative of x minus 1 into x minus 2 but x minus 3 into x minus 4​

Answer 1

$x - 1 \times x - 2 = x - 3 \times x - 4$

${x}^{2} - 2x - 1x + 2 = {x}^{2} - 4x - 3x + 12$

${x}^{2} - 3x + 2 = {x}^{2} - 7x + 12$

${x}^{2} - {x}^{2} - 3x + 7x = 12 - 2$

$4x = 10$

$x = 10 \div 4$

$x = 5 \div 2$

$x = 2.5$

It may be right answer.