find the derivative of x3 + y3 = 3axy
Answers
Answered by
13
here is ur answer.......
Attachments:
Answered by
1
Answer:
x3 +y3 = 3a xy
3x2 + 3y2 dy/dx = 3a [x dy/dx +y ]
3x2 + 3y2 dy/dx + y
dy/dx ( 3y2 - 3ax ) = y - 3x2
dy/dx = y-3x2/3y2-3ax
I hope that this will help you
Step-by-step explanation:
Similar questions