Question

find the derivative of x3tanx​

Answer 1

$y = {x}^{3} tanx \\ \frac{dy}{dx} = {x}^{3} {sec}^{2} x + tanx(3 {x}^{2} ) \\ \frac{dy}{dx} = {x}^{2} (x {sec}^{2} x + 3tanx)$