find the derivative of xsecx/3x+2
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answer is { (3x+2)(xsecxtanx+secx)-3xsecx } / (3x+2)^2
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Derivative of a fraction... d/dx (u/v)
u = x secx.
u' = x Secx tanx + secx * 1 = secx (x tanx + 1)
v = 3x +2. v' = 3
d/dx ( u/v)
= [v * u' - u * v' ]/ v²
= [ (3x+2) secx (x tanx + 1) - x secx * 3 ] / (3x+2)²
= Secx * [ 3 x² tan x + 2x tan x + 2 ] / (3x+2)²
u = x secx.
u' = x Secx tanx + secx * 1 = secx (x tanx + 1)
v = 3x +2. v' = 3
d/dx ( u/v)
= [v * u' - u * v' ]/ v²
= [ (3x+2) secx (x tanx + 1) - x secx * 3 ] / (3x+2)²
= Secx * [ 3 x² tan x + 2x tan x + 2 ] / (3x+2)²
kvnmurty:
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