find the derivative of y = 4x²sinx
Answers
Answered by
1
Step-by-step explanation:
du
=2x and
du
dy
=cosu
and we can write
dx
dy
=
du
dy
⋅
dx
du
. Hence,
dx
dy
=(cosu)⋅(2x)=2x⋅cos(x
2
−4).
Answered by
0
Step-by-step explanation:
Using formula
derivative of u.v = u.(d/dx) v + v.(d/dx u)
= 4 [ x²cosx + 2xsinx]
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