Question

find the derivative of y = 4x²sinx​

Answer 1

Step-by-step explanation:

du

=2x and

du

dy

=cosu

and we can write

dx

dy

=

du

dy

⋅

dx

du

. Hence,

dx

dy

=(cosu)⋅(2x)=2x⋅cos(x

2

−4).

Answer 2

Step-by-step explanation:

Using formula

derivative of u.v = u.(d/dx) v + v.(d/dx u)

= 4 [ x²cosx + 2xsinx]