Find the derivative of y=log e sin x
Answers
Answered by
8
Answer:
Since derivative of log x is 1/x and derivative of sin x is cos x. Therefore, 1/sin x*cos x is the derivative of given function. This can be further written as cot x.
Answered by
12
Answer:
ans is cot x
Explanation:
y=loge sinx
dy/dx= d ( loge sin x)/dx
FOLLOWING THE DOUBLE CHAIN RULE:
dy/dx= 1/sinx *d(sin x )/dx [since d( loge x) /dx = 1/x]
= 1/sin x * cos x [since d(sinx)/dx= cos x]
cosx / sinx = cotx
therefore dy/dx = cot x
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