Question

Find the derivative of Y= (log*sin x) tan 4x​

Answer 1

Answer:

$y = logsinx \: tan4x \\ \frac{dy}{dx} = logsinx \frac{d}{dx} tan4x + tan4x \frac{d}{dx} logsinx \\ = logsinx {sec}^{2} 4x.4 + tan4x \frac{1}{sinx} cosx \\ = 4 {sec}^{2} xlogsinx + tan4xcotx$