Physics, asked by piyasharma42493, 10 months ago

find the derivative of y= loge sinx.​

Answers

Answered by Anonymous
1

Answer:

Given that y=log(sinx), we need to find the value of

dx

dy

We know that the derivative of log(x) w.r.t x is

x

1

dx

dy

=

dx

d

(log(sinx))=

sinx

1

×

dx

d

(sinx)=

sinx

1

×cosx=cotx

Hence,

dx

dy

=cotx

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