find the derivative of y= loge sinx.
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Answer:
Given that y=log(sinx), we need to find the value of
dx
dy
We know that the derivative of log(x) w.r.t x is
x
1
⟹
dx
dy
=
dx
d
(log(sinx))=
sinx
1
×
dx
d
(sinx)=
sinx
1
×cosx=cotx
Hence,
dx
dy
=cotx
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