Find the derivative of y=sin-1[2x/1+x^]
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y=sin-1{2x/1+x^2}
let x=tantheta
so,y=sin-1{2tantheta/1+tan^2theta}
or,y=sin-1{sin2theta}
or,y=2theta
so derivative of 2theta is zero.
Hope this is the right answer and I could help you.
let x=tantheta
so,y=sin-1{2tantheta/1+tan^2theta}
or,y=sin-1{sin2theta}
or,y=2theta
so derivative of 2theta is zero.
Hope this is the right answer and I could help you.
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