Question

find the derivative of y=x^3sinx

answer fast....plz genius

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Answer 1

Answer:

3 x  ^2sin ( x ) +x^ 3 cos ( x )

simplifying more

x ^2 ( 3 sin ( x) + x cos ( x ) )

Hope it Helps :)

Step-by-step explanation:

Answer 2

Answer:

$\implies$ dy/dx = x³cos(x) + 3x² sin(x)

$\large\underline\mathrm{Solution}$

$\implies$ y=x^3sinx

Differential both side of the equation.

d(y)/dx = d /dx (x³ sin(x))

The derivative of y with respect to x is y',

$\implies$ x³ cos(x) + 3x² sin(x)

$\implies$ y' = x³ cos(x) + 3x² sin(x)

Replace y' with dy/dx

$\implies$ dy/dx = x³ cos(x) + 3x² sin(x)