Find the derivative of y = (x2 +5)(3x+1).
Answers
Answered by
0
Answer:
y = (x2 +5)(3x+1)
y = x2(3x+1)+5(3x+1)
y = 3x3+x2+15x+5
dy/dx = 9x2+2x+15
feel free to correct me if I'm wrong
Answered by
1
y ' = 4 x ( x 2 + 5 )
Explanation:
Use the chain rule and the power rule:
( u n) ' = n u n − 1 u ' y ' = 2 ( x 2 + 5 ) 1 ( 2 x ) y ' = 4 x ( x 2 + 5 )
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