Question

find the derivative root cot
$find the drivative root cotx$
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Answer 1

$\frac{d\sqrt{cotx} }{dx}$

note (d(cotx)/dx=−cosec^2x)

rewrite f(x) as f(x)=(cotx)^1/2

Differentiate using   chain rule

f'(x)=((cotx)/2)^(−1/2)x d(cotx)/dx

=1/2(cotx)^(−1/2).(−cosec2x)

'tidying up' to obtain f'(x)=−cosec^2 x/2√cotx