Math, asked by Anonymous, 6 months ago

Find the derivative:

f(x) = \frac{(x^2 + ax + b)}{\sqrt{a+b} }

Where 'a' and 'b' are constants

Answers

Answered by Anonymous
3

The derivative of a function y = f (×) of

a variable x is a measure of the rate at which the value of the function changes with respect to the change of the variable x.

It is called the the derivative off with respect to x.

one of the example for your question;

1]

f = (x) \frac{1}{x}

Rewrite

 rewrite \: \frac{1}{x} as  x - 1

 \frac{d}{dx} ( {x} - ^{1} )

differentiate using the power rule which states that

 \frac{d}{dx} ( {x}^{n} )is \: nx - 1 \: where \: n = 1.

 { - x}^{ - 2}

rewrite the expression using the negative component rule

 {b}^{ - n}  =  \frac{1}{bn}

  \frac{ - 1} {x2}

f(x) =  \frac{1}{x}

I hope it helps you buy my solution.

peace ✌

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