Question

find the derivatives of e^(2logx)​

Answer 1

e^-2logx

we know that [alogb]=log(b^a), using this fact we write like

=e^log(x^(-2))

=e^log(1/x^2)

also here base of log is “e” so [e^log(a)]=a use this in above term than we get answer.

=1/x^2

Answer 2

Hello!!

Have a look in attachment!!