find the derivatives of sin²xcos²x
Answers
Answered by
0
Step-by-step explanation:
sin²xcos²x
=d/dx sin²xcos²x
=sin²x2cosx(-sinx)+cos²x2sinxcosx
=2(cos³xsinx-sin³xcosx)
=2cosxsinx(cos²x-sin²x)
=(sinx+cosx)³(cosx-sinx)
Similar questions