Question

find the derivatives of tan³x​

Answer 1

Step-by-step explanation:

f(x) = tan³x

df(x)/dx = d{tan³x}/dx

we know, if y = gⁿ(x) then, \frac{dy}{dx}=n.g^{n-1}(x).g'(x)

dx

dy

=n.g

n−1

(x).g

′

(x)

so, f'(x) = d{tan³x}/dx = 3tan²x. d{tanx}/dx

= 3tan²x. sec²x

= (√3tanx. secx)²

Answer 2

Answer:

3 sec square x

Step-by-step explanation:

dy/dx = d/ dx tancube x

= 3 sec square x