Question

find the derivatives of the following function f(x) =(x^2-3) (4x^3+1)​

Answer 1

Step-by-step explanation:

d/dx {(x^2-3) (4x^3+1)}. =(x²-3) d/dx(4x³+1)+(4x³+1) d/dx(x²-3) =(x²-3)(12x²+0)+(4x³+1)(2x-0)

=12x⁴-36x²+8x⁴+2x

=20x⁴-36x²+2x

Note:

• d/dx (xⁿ)= nxⁿ`¹
• d/dx (C)= 0

[Where,C= Constant term.]

• d/dx (uv) = u dv/dx+v du/dx

Answer 2

Answer:

ans is

$20 {x}^{4} - 36 {x}^{2} + 2x$