find the derivatives of the sin(cos x) with respect to x
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1
Answer:
just apply chain rule
derivative will be(sin(cosx))(-sinx)
Answered by
1
Answer:
Step-by-step explanation:y=sin(cos x)
Let cos x be u
y=sin u
dy/du=cos u
u=cos x
du/dx=-sinx
dy/dx=dy/du×du/dx
dy/dx=cos u (-sin x)
dy/dx=cos cos x(-sin x)
dy/dx=-cos(cos x sin x)
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