Math, asked by vikramgaba199, 9 months ago

find the derivatives of xtanx ÷secx + tanx

Answers

Answered by debismita

0

Answer:

y=xtanx/(secx+tanx)

y'=(secx+tanx)(xsec^2x+tanx)-(xtanx)(secx tanx+sec^2x)/(secx+tanx)^2.

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