Math, asked by snehapoornan2002, 2 months ago

find the derivatives of y=(2x+3) (3x^2)

Answers

Answered by bagkakali

0

Answer:

y =(2x+3)(3x^2)

dy/dx=(2x+3).6x+3x^2.2

=12x^2+18x+6x^2

=18x^2+18x

=18x(x+1)

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