Math, asked by aclssgamingff, 2 months ago

Find the derivatives of Y=x²×log sinx​

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Answered by sandy1816
2

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given  \:  \: y = x {}^{2} logsinx \\differentiate \: w.r.t \:  \: x  \\  \frac{dy}{dx}  =  {x}^{2}  \frac{d}{dx} logsinx + logsinx \frac{d}{dx} {x}^{2}   \\  =  {x}^{2}  \frac{1}{sinx} cosx + logsinx \: 2x \\  =  {x}^{2} cotx + 2xlogsinx

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