Question

Find the derivatives w.r.t.x:
x³ + 4x² + 5x + 7

Answer 1

derivates of =x^3+4x^2+5x+7
w.r.t
dx^3/dx+d 4x^2/dx+d 5x/dx+7
3x^2+8x+5+0

Answer 2

Answer:

Derivative = 3x² + 8x + 5

Step-by-step explanation:

In the given equation,

f(x) = x³ + 4x² + 5x + 7

So,

To find the derivative of the given function.

On differentiating w.r.t 'x' we get,

$f(x) = x^{3} + 4x^{2} + 5x + 7\\So,\\f'(x)=\frac{d}{dx}f(x)=\frac{d}{dx}(x^{3} + 4x^{2} + 5x + 7)\\f'(x) =3x^{2}+8x+5$

Therefore, on differentiation we get,

3x² + 8x + 5

Hence, the derivative is given by,

3x² + 8x + 5