Question

Find the descriminant value of equation 2y²-5y+10=0

Answer 1

Answer:

-55

Step-by-step explanation:

in the quadratic equation 2y^2-5y+10

first term(a) = 2

second term(b) = -5

third term(c) = 10

in quadratic equation discriminant= b^2-4ac

= (-5)^2 - 4(2×10)

= 25-4(20)

=25-80

= -55

so the discriminant in the quadratic equation 2y^2-5y+10= -55

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