find the descriminate of the quadratic eqation - 3√3x2+10x+√3-0
Answers
Answered by
1
hey mate here is your answer
3√3x²+10x+√3 =0
here ,a=3√3 ,b=10 ,c=√3
discriminant= b²-4ac
= 100-36
= 64
here , 64 is a perfect square number
so the roots are real and unequal
hope it may help you
PLZ MARK ME THE BRAINLIEST!!!
Similar questions