Question

find the determinant value of quadratic equation

$\sqrt{2x ^{2} } + 4x + 12 \sqrt{2 = 0}$
​

Answer 1

Refer The Attachment ⬆️

• Roots are $\Large\red{\sf{\frac{-1±\sqrt{5}i}{\sqrt{2}}}}$

☞ i here means IOTA used to remove negative sign from the root.

ᴍʀꜱᴏᴠᴇʀᴇɪɢɴ࿐

Hope This Helps!!