find the diagonal and perimeter of a square whose area is 400 per metre square
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20√2 m and 80 m
Step-by-step explanation:
side of square = √400= 20 m
Perimeter of square = 4×side=4×20=80 m
(Diagonal)^2=2×{side}^2=√800=20√2 m
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Answer:
Step-by-step explanation:
Side of the square= square root of 400=20m^2
Now, perimeter of a square= 4*side of the square=4*20= 80 m
Also, area of a square=(diagonal)^2/2
So, 400= d^2/2
d^2=800
Therefore, d=square root of 800 = 20root2
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