Question

Find the diagonal of a parallelogram if its length is 60m and its breadth is 40m.

Answer 1

Solution

Using diagram 
ABCD 
s = 1/2(60+40+80) = 90 m
and use 
triangle area = Sqrt{s(s-a)(s-b)(s-c)} 
*2
hope you got ur answer

Full solution


S(△ABC)=60+80+402=90S(△ABC)=60+80+402=90

ar△ABDar△ABD

=90(90−80)(90−60)(90−40)−−−−−−−−−−−−−−−−−−−−−−−√=90(90−80)(90−60)(90−40)

=90×10×30×50−−−−−−−−−−−−−−√=90×10×30×50

=30015−−√m2=30015m2

ar□ABCE=2×ar△ABDar◻ABCE=2×ar△ABD

=60015−−√m2=60015m2

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Answer 2

Diagonal will be square root of (60^2 + 40^2)

root of (3600+1600)

root of(5200)

20 root 13