Question

Find the diagonal of a rectangle whose L=35cm & B=12cm.
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Answer 1

HEYA!!

plz refer the attachment above.

Your Answer should be AC=BD=37cm.

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Answer 2

$\mathfrak{\large{\underline{\underline{Answer :-}}}}$

The Diagonal of the Rectangle is 37 cm.

$\mathfrak{\large{\underline{\underline{Explanation :-}}}}$

$\textsf{\underline{\underline{Given :}}}$

Length of the Rectangle = 35 cm

Breadth of the Rectangle = 12 cm

$\textsf{\underline{\underline{To Find :}}}$

Its Diagonal

$\textsf{\underline{\underline{Solution :}}}$

Refer the Attachment

By Pythagoras Theorum -

In ∆ ACD :

• Perpendicular = 12 cm
• Base = 35 cm
• Hypotenuse = x

$\boxed{\sf{Hypotenuse^{2}=Perpendicular^{2}+Base^{2}}}$

$\sf{\longrightarrow} \: {x}^{2} = {12}^{2} + {35}^{2}$

$\sf{\longrightarrow} \: {x}^{2} = 144 + 1225$

$\sf{\longrightarrow} \: {x}^{2} = 1369$

$\sf{\longrightarrow} \: x = \sqrt{1369}$

$\sf{\longrightarrow} \: x = 37$

Hypotenuse is 37 cm.

$\therefore$ The Diagonal of the Rectangle is 37 cm.