find the diagonal of a rectangle whose length and breadth are 16 by 31 cm. and 12 by 31 cm.
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Answered by
2
Answer:
37
Step-by-step explanation:
Let □ ◻ABCD be the given rectangle.
AB = 12 cm, BC 35 cm
In ∆ABC, ∠B = 90° [Angle of a rectangle]
∴ AC = AB + BC [Pythagoras theorem]
= 122 + 352 = 144 + 1225 = 1369
∴ AC = √ 1369 1369 [Taking square root of both sides]
= 37 cm ∴ The diagonal of the rectangle is 37 cm
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Answered by
1
Answer:
400/961 which is approx 0.4162
Step-by-step explanation:
assume a rectangle named ABCD whose Length and breadth are 16/31 and 12/31 respectively.
AB= 16/31, BC= 12/31
by Pythagoras Theorem :
AC² = AB² + BC²
= (16/31)² + (12/31)²
= (256/961) + (144/961)
= 400/961
which is approx 0.4162
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