Question

find the diagonal of a rectangle whose length is 16 cm. and area is 192sq.cm.​

Answer 1

Answer:

are = l X b

192 = 16 X b

192/16 = b

b = 12

breadth = 12cm length = 16

We have to find diagonal

By Pythagoras theorem 16² + 12² = diagonal²

256 + 144 = diagonal 2

400 = diagonal²

400 root = diagonal

20 is the answer

20.

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Answer 2

Step-by-step explanation:

It is given that , area of rectangle is 192sq.cm.

Area=Length×Bredth

⇒192=16×BC

⇒BC=

16

192

⇒BC=12cm...(1)

According to pythagoras theorem,

In△ABC

AB 2

+BC 2

=AC 2

⇒(16) 2

+(12) 2

=A 2

⇒256+144=AC 2

⇒AC 2

=400

⇒AC=20cm

Hence , the length of a diagonal of the rectangle is 20cm.