Question

find the diagonal of a rectangle whose length is 16 cm and area is 192 sq. cm​

Answer 1

Given, length = 16 cm and area = 192 sq.cm.

Then, breadth = (192/16)cm = 12 cm

Thus, diagonal of the rectangle

$\sqrt{ {16}^{2} + {12}^{2} } \: cm \\ = \sqrt{256 + 144} \: cm\\ = \sqrt{400} \: cm \\ = 20 \: cm$

HOPE THIS COULD HELP!!!