Question

. Find the diagonal of a rectangle whose length is
35 cm and breadth is 12 cm......​

Answer 1

Step-by-step explanation:

Given,

Breadth of rectangle = 12 cm

Length = 35 cm

Length of diagonal :-

According to the Pythagoras theorem ,

c² = a² + b²

Here ,

c is diagonal

a is length

&

b is breadth

According to the question :-

c² = a² + b²

c² = 35² + 12²

c² = 1225 + 144

c² = 1369

c = √1369

c = 37

Hence the required length of diagonal is 37 cm

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Answer 2

Answer:-

The Diagonal of the following rectangle is 37

Explanation:-

Given :

Length of rectangle = 35 cm

Breadth of rectangle = 12 cm

To find :

Diagonal of the rectangle

Solution :

We know that, the formula of the Diagonal of a rectangle is:-

$D = \sqrt{ {length}^{2} + {breadth}^{2} }$

$= > D = \sqrt{ {35}^{2} + {12}^{2} }$

$= > D = \sqrt{1225 + 144}$

$= > D = \sqrt{1369}$

$= > D = 37$

Hence, The Diagonal of the rectangle is 37.

More information :-

$\bullet$ A rectangle has two diagonals.

$\bullet$ The Diagonal divides the rectangle into two halves or two congruent right-angles.

$\bullet$ The Diagonal is drawn between the opposite corners of the rectangle.

$\bullet$ Each triangle's area is the half of rectangle's area. The two triangles have the same area and perimeter.