Find the diagonal of a rectangle whose length of 40 cm and breadth is 9 cm
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Answered by
3
diagonal=√length^2+breadth^2
diagonal=√40^2+9^2
diagonal=√1600+81
diagonal=√1681
diagonal= 41
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Answered by
4
Answer:
41 cm
Step-by-step explanation:
According to Pythagoras Theorem,
(Diagonal)² = (Length)² + (Breadth)²
Given that,
Length = 40 cm
Breadth = 9 cm
=> (Diagonal)² = (40)² + (9)²
=> (Diagonal)² = 1600 + 81
=> (Diagonal)² = 1681
=> Diagonal = √1681
=> Diagonal = 41 cm
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