Question

find the diagonal of a rectanglewhose length is 12 cm and breadht is 5 cm​

Answer 1

Answer:

Given,

length = 12 cm

breadth = 5 cm

Diagonal of rectangle =

$\sqrt{ {l}^{2} + {b}^{2} } \\ \sqrt{ {(12 \: cm)}^{2} + {(5 \: cm)}^{2} } \\ \sqrt{144 \: {cm}^{2} + 25 \: {cm}^{2} } \\ \sqrt{169 \: \: {cm}^{2} } \\ 13 \: cm$

Therefore, Diagonal of rectangle is 13 cm...

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Answer 2

Answer:

(hyp)^2 =(perp)^2 +(base)^2

(hyp)^2=12^2+5^2

(hyp)^2= 144+25

(hyp)^2= 169

hyp= √ 169

hyp = 13