Question

find the diagonal of a square whose area is 64 m²
please tell​

Answer 1

8 m

Step-by-step explanation:

area is 64

so side will be 8

by Pythagoras

8²+8²=diagonal ²

64+64=128

diagonal is 8√2 m

Answer 2

To finD:

find the diagonal of a square whose area is 64 m²

GiveN:

Area of the square=64 m²

ThereforE:

1 side of a square=$\sqrt{64}$ m

                              =$\sqrt{8 * 8}$ m

                             =8 m

SolutioN:

Diagonal of the square=  $\sqrt{8^2 + 8^2}$    m

                                     =   $\sqrt{64 + 64}$   m

                                     =   $\sqrt{128}$         m

                                     = 8$\sqrt{2}$ m

ChecK:    

1 Side of the square= 8 m

Used formulA:

1 Side of the square=$\sqrt{Area of the square}$

Diagonal of the square=$\sqrt{Side^2 + Side^2}$

Answer:

8$\sqrt{2}$ m