Question

Find the diagonal of a square whose area is 64m.sq
​

Answer 1

Step-by-step explanation:

Area of sqyare = side^2

Let the side of square be x

so x^2=64

x=8

So side of given square is 8 m.

Diagonal of square =

$\sqrt{x { }^{2} + {x}^{2} }$

=

$\sqrt{2x {}^{2} }$

=

$\sqrt{128 }$

=

$8 \sqrt{2 }$

Answer 2

Solution:-

Given:-

Area = 64 ${m}^{2}$

To Find:-

Diagonal of the square.

Formula:-

Diagonal = $\sqrt{2} \times side$

Area = ${(side)}^{2}$

By the Problem:-

$\\ Area = {(side)}^{2} \\ 64 = {(side)}^{2} \\ side = \sqrt{64} \\ side = 8 \: m$

$Diagonal = \sqrt{2} \times side \\ Diagonal = \sqrt{2} \times 8 \\ Diagonal = 8 \sqrt{2} \: m$

This can help you.