Find the diagonal of a square whose area is 64sq.m
Answers
Answer:
Heya Mate..!!
We know that, the diagonal of a square along with any two adjacent sides of a square makes a right traingle where the two sides are the base and height and the diagonal is the hypotenuse.
So, to find the hypotenuse we have to use the Pythagoras' Theorem.
Pythagoras' Theorem states that...
(Hypotenuse)^2=(Base)^2+(Height)^2
Again, given area=64 sq. m
=> side×side=64 sq. m
=> side=√64 =8 m
So, let AC= Hypotenuse
AB= Base = 8 m
BC= Height = 8 m
Now, using Pythagoras' Theorm,
AC=√{(AB)^2 + (BC)^2}
AC=√{(8)^2 + (8)^2}
AC=√(64+64)
AC=√128
AC= 11.31 m
:. The diagonal of the given square= 11.31 m
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