Question

Find the diagonal of a square whose each sides is 16 cm

Tell me fast!!!
I will mark you as the Brainliest​

Answer 1

Diagonal Of Square = 22.62 cm

Step-by-step explanation:

GIVEN

Sides = 16 cm

___________________________

TO FIND

Diagonal

___________________________

FORMULAS

Area Of Square = Side × Side = Side²

Perimeter Of Square = 4 × Side

Diagonal Of Square = √2 × Side

___________________________

We know that,

Diagonal Of Square = √2 × Side

Diagonal Of Square = √2 × 16

Diagonal Of Square = 1.41421356 × 16

Diagonal Of Square = 22.62

Diagonal Of Square = 22.62 cm

___________________________

We can find the diagonal by Pythagoras Theorem

We know that,

Hypotenuse² = Base² + Height²

Hypotenuse² = 16² + 16²

Hypotenuse² = 256 + 256

Hypotenuse² = 512

Hypotenuse² = √512

Hypotenuse = 22.62

Hypotenuse = 22.62 cm

Answer 2

Question:

Find the diagonal of a square whose each sides is 16 cm

Given :

• Side of the square = 16 cm

To find :

• Diagonal of the square.

Solution :

Using Pythagoras Therom we can find the diagonal of the square.

We know that base and perpendicular of the right angled triangle are 16 cm and 16cm respectively.

Base of triangle = 16cm

Perpendicular of triangle = 16cm

Hypotenuse = ?

Using Pythagoras theorem :

$\boxed {\bf {Hypotenuse}^2 = {Base}^2+ {Perpendicular}^2 }$

$: \implies \tt {{H}^2 = {B}^2 + {P}^2 }$

$: \implies \tt {{H}^2 = {16}^2 + {16}^2}$

.$: \implies \tt {{H}^2 = 256 + 256}$

$: \implies \tt {{H}^2 = 512}$

$: \implies \tt {H = \sqrt{512}}$

$: \implies \tt {H = 22.62 cm}$

Therefore, diagonal of the square = 22.62cm.