Question

Find the diagonal of a square whose perimeter is 60 cm.

Answer 1

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Here is your answer.

Perimeter = 60 cm

$4(side) = 60 \\ \\ side = \frac{60}{4} \\ \\ = 15cm$
Therefore, Side= 15cm

Now,
$diagonal = \sqrt{ {side}^{2} + {side}^{2} } \\ \\ diagonal = \sqrt{ {15}^{2} + {15}^{2} } \\ \\ = \sqrt{125 + 125} \\ = \sqrt{250} \\ \\ =5 \sqrt{10} cm$
Therefore, The Diagonal is $5 \sqrt{10}$

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Answer 2

Answer:

Perimeter of a square = 4a

60 = 4a

60/4 = a

15 = a

So a is 15 cm

In right angle triangle, right angle at D.

AC square = AD square+CD square

AC = √225+225

= √500

= 10√5cm