Question

Find the diagonal of a square whose side is 10 cm.
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Answer 1

Answer:

The side of square is 10 cm

In right angled △ABD

${AB}^{2} + {AD}^{2} = {BD}^{2}$

[according to Pythagoras theorem]

(10) ^2 +(10) ^2=BD 2 $

100+100=BD ^2

BD ^2=200

BD=10 √2 cm

∴ Diagonal of square =10 √2 cm.

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