Question

Find the diagonal of a square whose side is 10cm.

please help it's urgent ​

Answer 1

Answer:

The side of square is 10 cm

In right angled △ABD

AB ²+AD²=BD ²

[according to Pythagoras theorem]

(10) ²+(10) ²=BD²$

100+100=BD ²

BD ²=200

BD=10 √2cm

∴ Diagonal of square =10 √2 cm.

Answer 2

Answer:

ABCD is an Square having length of sides a and d is its diagonal.

Here sides AB = BC = CD = DA = a = 10 cm

Now consider the triangle ABC,which is a right angle triangle with ∠B = 90°

By Pythagoras theorem

AC² = AB² + BC²

d² = a² + a²

d² = (10cm)² + (10cm)²

d² = 200 cm²

So, d = √ (200cm²) = (10√ 2)cm

Now because every squares have two diagonals of equal length, So Diagonal AC = BD = d = (10√ 2)cm

Step-by-step explanation:

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