Question

find the diagonal of cuboid​

Answer 1

Question given:

To find the diagonal of the cuboid given.

Given:

• Lenght= 8 cm
• Breadth= 6 cm
• Height= 2 cm

To find:

• →The diagonal AG of cuboid.

Solution:

We know that,

$\rm\blue{Diagonal~of~cuboid=}\sqrt\blue{l²+b²+h²}$

According to Question:

$\rm{Diagonal~of~cuboid=}\sqrt{l²+b²+h²}$

Putting the values,

$\rm{Diagonal~of~cuboid=}\sqrt{(8)²+(6)²+(2)²}$

$\rm{Diagonal~of~cuboid=}\sqrt{64+36+4}$

$\rm{Diagonal~of~cuboid=}\sqrt{100+4}$

$\rm{Diagonal~of~cuboid=}\sqrt{104}$

$\rm{Diagonal~of~cuboid=2}\sqrt{26}cm$

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$\sf\underline\red{More~information:-}$

Cuboid:

A solid attached by six rectangular plane faces is known as a cuboid.

$\rm\mapsto{Volume~of~cuboid=(length+breadth+height)cubic~units.}$

$\rm\mapsto{Diagonal~of~cuboid=}\sqrt{l²+b²+h²}$

$\rm\mapsto{Total~surface~area~of~cuboid=2(lb+bh+lb)}$

$\rm\mapsto{Lateral~surface~area~of~cuboid=[2(l+b)×h]}$

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⠀⠀⠀Hope it's helpful

Answer 2

Answer:

Given:

Lenght= 8 cm

Breadth= 6 cm

Height= 2 cm

To find:

→The diagonal AG of cuboid.

Solution:

We know that,

$\rm {Diagonal \: of \: the \:cuboid} = \sqrt {l² + b² + h²}$

Putting the values,

$\rm{Diagonal~of~cuboid=}\sqrt{64+36+4}$

$\rm{Diagonal~of~cuboid=}\sqrt{100+4}$

$\rm{Diagonal~of~cuboid=}\sqrt{104}$

$\rm{Diagonal~of~cuboid=2}\sqrt{26}$