Find the diagonal of rectangle whose length is 16 cm. and area is 192 sq. cm.
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Answer:
20 cm
Step-by-step explanation:
Given:
Length (L) = 16 cm
Area (A) = 192 sq.cm
To find:
Diagonal (D)= ?
Formula:
A = L√D^2 - L^2
Solution:
A = L√D^2 - L^2
192 = 16 √D^2 -16^2
192 = 16 √D^2 -256
192÷16 = √D^2 - 256
12 = √D^2 - 256
12^2 = (√D^2 - 256)^2
144 = D^2 - 256
D^2 = 144 + 256
D^2 = 400
D = √400
D = 20 cm
Therefore, the length of the diagonal of the rectangle whose length is 16 cm and Area is 192 sq.cm is 20 cm.
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