Question

Find the diagonal of the cube whose each edge is 4cm​

Answer 1

Answer:

Side of cube, a = 4cm

Alternate sides of a cube are at 90%, so the diagonal becomes hypotenuse and the sides become perpendicular and base.

Then, by pythagoras theorem

H^2 = P^2 + B^2

H^2 = (4*4)+(4*4)

H^2 = 16 + 16

H=

\sqrt{32}32

H= 5.65685cm

Diagonal of cube = 5.6cm approx

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Answer 2

d≈6.93

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