Find the diagonal of the rectangle whose sides are 80cm and 60cm
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100 cm
Step-by-step explanation:
d=√w²+l² = √ 60² + 80² = √ 3600+ 6400=
√ 10000 = 100
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Answer :
It’s is a right angle triangle . AB = 80cm , BC = 60cm , AC is the diagonal of rectangle.
Ac^2 = AB^2 + BC ^2
AC^2 = (80 cm)^2 + (60 cm)^2
AC^2 = (6400 cm^2)+ (3600 cm^2)
AC^2 = 10,000 cm^2
AC = root ( 10,000 cm^2)
AC = 100 cm
Thus, answer is the diagonal of the rectangle is 100 cm
It’s is a right angle triangle . AB = 80cm , BC = 60cm , AC is the diagonal of rectangle.
Ac^2 = AB^2 + BC ^2
AC^2 = (80 cm)^2 + (60 cm)^2
AC^2 = (6400 cm^2)+ (3600 cm^2)
AC^2 = 10,000 cm^2
AC = root ( 10,000 cm^2)
AC = 100 cm
Thus, answer is the diagonal of the rectangle is 100 cm
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